Jorge is painting a rectangular mural. Its length is 2 ft less than twice its width. Its area is 264 ft2. Find the dimensions of the mural.

Answer 1

length = 2(width) - 2

l = 2w - 2

area = lw

area = (2w-2)(w)

264 = 2w^2-2w

0 = 2w^2 -2w-264

0= 2(w^2 - w -132)

divide both sides by 2

0 = w^2 - w - 132

Factor and solve for w. you only want the positive value since it is a width. Once you have the width, use l=2w-2 to find the length. Check by multiplying your length times the width to see if you get 264. Be sure to use your units of feet.

Answer 2

wedsa

Answer 3

I'm sorry, I don't understand what you mean by "wedsa". Can you please provide more context or rephrase your question or statement?

Answer 4

No