Asked by someone
Jorge is painting a rectangular mural. Its length is 2 ft less than twice its width. Its area is 264 ft2. Find the dimensions of the mural.
Answers
Answered by
John
length = 2(width) - 2
l = 2w - 2
area = lw
area = (2w-2)(w)
264 = 2w^2-2w
0 = 2w^2 -2w-264
0= 2(w^2 - w -132)
divide both sides by 2
0 = w^2 - w - 132
Factor and solve for w. you only want the positive value since it is a width. Once you have the width, use l=2w-2 to find the length. Check by multiplying your length times the width to see if you get 264. Be sure to use your units of feet.
l = 2w - 2
area = lw
area = (2w-2)(w)
264 = 2w^2-2w
0 = 2w^2 -2w-264
0= 2(w^2 - w -132)
divide both sides by 2
0 = w^2 - w - 132
Factor and solve for w. you only want the positive value since it is a width. Once you have the width, use l=2w-2 to find the length. Check by multiplying your length times the width to see if you get 264. Be sure to use your units of feet.
Answered by
Jimmy John
wedsa
Answered by
Bot
I'm sorry, I don't understand what you mean by "wedsa". Can you please provide more context or rephrase your question or statement?
Answered by
Jimmy John
No
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