Question
UMM.. I keep coming up with the wrong answer? How do I calculate this?
1. Calculate the number of Li atoms in 9.9 moles of Li.
Express your answer using two significant figures.
2. Calculate the number of CO2 molecules in 3.13×10−2 mole of CO2.
3.Calculate the moles of Cu in 2.4×1021 atoms of Cu.
4.Calculate the moles of C2H6 in 8.60×1023 molecules of C2H6.
1. Calculate the number of Li atoms in 9.9 moles of Li.
Express your answer using two significant figures.
2. Calculate the number of CO2 molecules in 3.13×10−2 mole of CO2.
3.Calculate the moles of Cu in 2.4×1021 atoms of Cu.
4.Calculate the moles of C2H6 in 8.60×1023 molecules of C2H6.
Answers
There are 6.02E23 atoms in a mole of atoms or 6.02E23 molecules in a mole o molecules; actually, 6.02E23 anythings in a mole of anythings. Just as there are 12 in a DOZEN, 144 in a GROSS, 500 sheets in a REAM of paper,etc, there are 6.02E23 molecules in a mole. It's just another unit like dozen or gross. From your previous work it appears you like to work with unit factors so I'll stick with that.
a. 9.9 mol Li x (6.02E23 atoms/mol) = ? atoms Li.
b. 3.13E-2 mol CO2 x (6.02E23 molecules/mol) = ? molecules CO2
c. 2.4E21 atoms Cu x (1 mol Cu/6.02E23 atoms) = ? mols Cu
d. etc.
You will note that all of these are alike; they consist of taking the number you are given and multiplying by a factor. It's up to you to supply the factor. In this case it's (6.02E23 atoms/1 mol) or (6.02E23 molecules/1 mol) or (1 mol/6.02E23 whatevers)
a. 9.9 mol Li x (6.02E23 atoms/mol) = ? atoms Li.
b. 3.13E-2 mol CO2 x (6.02E23 molecules/mol) = ? molecules CO2
c. 2.4E21 atoms Cu x (1 mol Cu/6.02E23 atoms) = ? mols Cu
d. etc.
You will note that all of these are alike; they consist of taking the number you are given and multiplying by a factor. It's up to you to supply the factor. In this case it's (6.02E23 atoms/1 mol) or (6.02E23 molecules/1 mol) or (1 mol/6.02E23 whatevers)
I'm doing things on Mastering Chemistry dot com my homework.. I thought i was doing it right.. I was doing 9.9 * (6.02E23/1) It didn't like my significant figures.. It was wanting 6.0 * 10^24 as the answer, not 5.95 ugh... Thanks Dr. Bob.. Will probably be posting more for help! this stuff is hard, but you are a great help!!
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