Asked by frank
2x^2=-8x+10
I got
x=-2-1i
x=-2+1i
But every time I plug the numbers back into the equation I am not getting the sides to equal. Not sure how to use the imaginary i.
I got
x=-2-1i
x=-2+1i
But every time I plug the numbers back into the equation I am not getting the sides to equal. Not sure how to use the imaginary i.
Answers
Answered by
pat
you don't have to use the Quadratic formula for this, it is factorable upon rewriting, 2x^2+8x-10=0 and factoring out a 2, 2(x^2+4x-5)=0
You should get, 2(x+5)(x-1) making x = -5 and 1.
You should get, 2(x+5)(x-1) making x = -5 and 1.
Answered by
frank
My chemistry professor wants us to use the quadratic formula
Answered by
DrBob222
First you should factor out the 2 to leave X^2 + 4x -5 = 0. You should not be getting an i. Getting an i means you are a negative under the square root.
Your problem is that you're not doing the part under the square root sign correctly.
sqrt(b^2-4*a*c)
sqrt(16-4*1*-5)
sqrt(16+20)
sqrt(36)
+/- 6
so you have
(-4 +-6)/2 = -5,1
and 5,1 will satisfy the equation.
Your problem is that you're not doing the part under the square root sign correctly.
sqrt(b^2-4*a*c)
sqrt(16-4*1*-5)
sqrt(16+20)
sqrt(36)
+/- 6
so you have
(-4 +-6)/2 = -5,1
and 5,1 will satisfy the equation.
Answered by
frank
okay thank you
There are no AI answers yet. The ability to request AI answers is coming soon!