Question
Dr. Bob222 Please don't get frustrated with me, I'm really trying to figure this out... UGH!!
I'm starting over again... Please advise...
. Consider the following chemical equation:
TiCl4(g) + 2Mg(l) → Ti(s) + 2MgCl2(l)
3.54×107g of TiCl4(g) were reacted completely and 7.91×106g of Ti(s) was obtained in the experiment.
a. (10 points) Calculate the theoretical yield of Ti(s).
In order to find TY I have to find the limiting agent.. ?? ugh.. Ok, Ti=47.88 Cl4=35.45*4... To find moles in TiCl4 I take 3.54*10^7 * 1moleTiCl4/189.68 = 184,521.89 moles? But I need TY of Ti?? 7.91*10^6 * 1mole Ti/47.88=165,204.68 moles Ti???? I'm completely lost.. I guess I don't even know how to correctly find the moles of things?? I'm taking this class online at UTA with no help from a teacher and I'm trying to teach myself.. and I'm struggling so bad!!!! I think after your help I am doing it right then I confuse myself again..
b. (5 points) What is the actual yield of Ti(s) in this experiment? 7.91*10^6 it's given...
c. (10 points) Calculate the % yield of Ti(s) in this experiment. Percent yield is AY/TY so would it be?? 7.91*10^6/165,204.68?? the moles of Ti? or is that the TY of Ti? I'm so confused.. You said before you got the TY to be 8.9E6? how??
I'm starting over again... Please advise...
. Consider the following chemical equation:
TiCl4(g) + 2Mg(l) → Ti(s) + 2MgCl2(l)
3.54×107g of TiCl4(g) were reacted completely and 7.91×106g of Ti(s) was obtained in the experiment.
a. (10 points) Calculate the theoretical yield of Ti(s).
In order to find TY I have to find the limiting agent.. ?? ugh.. Ok, Ti=47.88 Cl4=35.45*4... To find moles in TiCl4 I take 3.54*10^7 * 1moleTiCl4/189.68 = 184,521.89 moles? But I need TY of Ti?? 7.91*10^6 * 1mole Ti/47.88=165,204.68 moles Ti???? I'm completely lost.. I guess I don't even know how to correctly find the moles of things?? I'm taking this class online at UTA with no help from a teacher and I'm trying to teach myself.. and I'm struggling so bad!!!! I think after your help I am doing it right then I confuse myself again..
b. (5 points) What is the actual yield of Ti(s) in this experiment? 7.91*10^6 it's given...
c. (10 points) Calculate the % yield of Ti(s) in this experiment. Percent yield is AY/TY so would it be?? 7.91*10^6/165,204.68?? the moles of Ti? or is that the TY of Ti? I'm so confused.. You said before you got the TY to be 8.9E6? how??
Answers
3.54 x 10^7 g TiCl4 x (1 mol/189.68 g) x (1 mol Ti/1 mol TiCl4) x (47.88 g/1 mol) = 8.94 x 10^6 g Ti
Percent yield is equal to the actual amount yield divided by the theoretical amount, so: 7.91 x 10^6 all divided by 8.94 x 10^6 = 88.5% yield
Is this right???
Is this right???
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