Asked by Lulu
2KClO3-2KCl+3O2
If this reaction produced 35.2 g of KCl, how much O2 was produced (in grams)?
If this reaction produced 35.2 g of KCl, how much O2 was produced (in grams)?
Answers
Answered by
DrBob222
Using the coefficients in the balanced equation lets you convert mols of mols of anything to anything in the equation.
mols KCl = grams/molar mass = approx 5 but that's an estimate.
5 mols KCl x (3 mols O2/2 mol KCl) = 5 x 3/2 = ? mols O2.
Then grams = mols o2 x molar mass O2.
mols KCl = grams/molar mass = approx 5 but that's an estimate.
5 mols KCl x (3 mols O2/2 mol KCl) = 5 x 3/2 = ? mols O2.
Then grams = mols o2 x molar mass O2.
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