Asked by Help2
A 5.0x10^-3 m^3 container holds 4.90 g gas when the pressure is 75.0 cm Hg and the temperature is 50.0 degrees C. What will be the pressure if 6.00 g of this gas is confined to a 2.0x10^-3 m^3 container at 0.0 degrees C?
Do I simply need to use the combined gas law or does the fact that they gave the masses change the rules? Thank you very much!!
Do I simply need to use the combined gas law or does the fact that they gave the masses change the rules? Thank you very much!!
Answers
Answered by
Damon
the mass is proportional to the number of mols n2/n1 = m2/m1
P1 V1 = n1 R T1 so n1 = P1 V1/R T1
P2 V2 = n2 R T2 so n2 = P2 V2/R T2
n2/n1 = m2/m1 = (P2 V2/P1V1)(T1/T2)
6/4.9 = (P2*2/75*5)(323/273)
solve for P2
P1 V1 = n1 R T1 so n1 = P1 V1/R T1
P2 V2 = n2 R T2 so n2 = P2 V2/R T2
n2/n1 = m2/m1 = (P2 V2/P1V1)(T1/T2)
6/4.9 = (P2*2/75*5)(323/273)
solve for P2
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