Asked by sally
Kim and Kent are on opposite sides of a canal, pulling a barge with tow ropes. Kim exerts a force of 50N at 20 degrees to the canal and Kent pulls at an angle of 15 degrees with just enough force so that the resultant force vector is directly along the canal. Find the number of Newtons with which Kent must pull and the magnitude of the resultant vector.
Answers
Answered by
Steve
Draw a diagram. Let the barge be in the canal, with Kim on the south shore, and Kent on the north shore, both pulling eastward. Then we have
Kim: u = <50cos20,-50sin20>
u = <46.98,-17.10>
Kent: v = <kcos15,ksin15>
= <0.966k,0.259k>
You want the resultant u+v to point eastward, so
-17.10 + 0.259k = 0
k = 66.02
So, Kent pulls with a force of 66 N.
u+v = <46.98+63.78,0> = <110.76,0>
Kim: u = <50cos20,-50sin20>
u = <46.98,-17.10>
Kent: v = <kcos15,ksin15>
= <0.966k,0.259k>
You want the resultant u+v to point eastward, so
-17.10 + 0.259k = 0
k = 66.02
So, Kent pulls with a force of 66 N.
u+v = <46.98+63.78,0> = <110.76,0>
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