For the reaction 4FeCl2(aq) + 3O2(g) → 2Fe2O3(s) + 4Cl2(g), what volume of a 0.650 M solution of FeCl2 is required to react completely with 8.58 × 1021 molecules of O2?

Answer 1

mols O2 = 8.58E21/6.02E23 = ?
Using the coefficients in the balanced equation, convert mols O2 to mols FeCl2. That's ? mols O2 x (4 mols FeCl2/3 mols O2) = ?
Then M FeCl2 = mols FeCl2/L FeCl2. You know M and mols, solve for L

Answer 2

ghgh