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The 5th term of an arithmetic sequence is 22 and the 15th term is 62. Find the 100th term and the sum of the first 60 terms.

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d=term difference÷position difference
62-22÷15-5=40÷10=4
d=4
tn=t1+(n-1)d
t100=6+100-1×4
=6+99×4=402 t1=t5-4d
=22-4×4
=22-16
=6

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