Asked by Anonymous
A 5.5 kg block is released from rest on a frictionless inclined plane making an angle of 23.3° with the horizontal. Calculate the time it will take this block when released from rest to travel a distance of 0.7 m along the ramp.
Answers
Answered by
Henry
sin23.3 = h/0.7
h = 0.7*sin 23.3 = 0.277 m.
h = 0.5g*t^2
h = 0.277 m.
g = 9.8 m/s^2
Solve for t.
h = 0.7*sin 23.3 = 0.277 m.
h = 0.5g*t^2
h = 0.277 m.
g = 9.8 m/s^2
Solve for t.
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