Asked by kudu
The position vectors for points P and Q are 4 I + 3 j + 6 j + 6 k respectively. Express vector PQ in terms of unit vectors I, j and k. Hence find the length of PQ, in simplified surd form.
Answers
Answered by
MathMate
It doe not look too clear what P and Q are, I am assuming the following.
P=(4,3,0)
Q=(0,6,6)
PQ = Q-P = <4,-3,-6> by subtraction
= 4i-3j-6k in unit vectors.
Length of vector
<x,y,z> = sqrt(x^2+y^2+z^2)
P=(4,3,0)
Q=(0,6,6)
PQ = Q-P = <4,-3,-6> by subtraction
= 4i-3j-6k in unit vectors.
Length of vector
<x,y,z> = sqrt(x^2+y^2+z^2)
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