Two six-sided dice are rolled. If the sum of the dots showing is odd, we get $10; otherwise, we lose $25. What is the expected value of this game?

Answer 1

If you look at the outcomes, you will see that half of the sums are even, the other half are odd.
So prob (even) = 1/2
prob(odd) = 1/2

expected value= (1/2)$10 + (1/2(-$25) = -7.5

Who would possible want to play this game ?

Answer 2

ur rong