Asked by brii

Two six-sided dice are rolled. If the sum of the dots showing is odd, we get $10; otherwise, we lose $25. What is the expected value of this game?

Answers

Answered by Reiny
If you look at the outcomes, you will see that half of the sums are even, the other half are odd.
So prob (even) = 1/2
prob(odd) = 1/2

expected value= (1/2)$10 + (1/2(-$25) = -7.5

Who would possible want to play this game ?
Answered by Isaac
ur rong
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