Answer g) first (trick question)
F = m a
a = 0
so net force on crate = 0
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a)
1 - friction
2 - m g gravity
3 - normal from ramp
so three
b) gravity, just one
c) none are horizontal
d)gravity, normal and friction
all have vertical components so three
e) normal and frictional, so two
f) m g down
g) we did to start
This one has been confusing me, can someone walk me through it? I'd like to know which formulas I need to use and everything.
A 121.0 -kg crate is sitting at rest on a ramp leading to the back of a truck.
a) How many forces are acting on the crate while it is at rest?
b) How many of the forces that are acting on the crate are along the vertical (parallel to the vertical) while is at rest?
c) How many of the forces that are acting on the crate are along the horizontal (parallel to the horizontal ) while is at rest?
d) How many of the forces acting on the crate act along the vertical (have a component along the vertical)?
e) How many of the forces acting on the crate act along the horizontal (have a component along the horizontal )?
f) What is the weight of the crate? (Express your answer in Newtons with the forward and the upward directions taken as positive and use 10 N/kg for g.)
g) What is the net force acting on the crate? (Express your answer in Newtons with the forward and the upward directions taken as positive.)
1 answer
2 answers