Question
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1. How many moles of oxygen will occupy a volume of 2.50 liters at 121.6 kPa and 331 K?
2. An unknown volume of chlorine gas (Cl2) is resting at 127 °C at a of pressure 152.4 kPa. If the gas weighs 191.4 g, what is the volume?
3. A 2.917 mole sample of an ideal gas at 285 K occupies a volume of 4.3 L. What is the pressure of the gas?
4. At what temperature would 2.10 moles of Kr gas have a pressure of 111.1 kPa and in a 25.0 L tank?
5. What is the volume of 146.2 grams of nitrogen gas (N2) molecules at STP?
6. What mass (NOT moles) of CO2 is needed to fill an 80.0 L tank to a pressure of 150.0 kPa at 27.0°C?
1. How many moles of oxygen will occupy a volume of 2.50 liters at 121.6 kPa and 331 K?
2. An unknown volume of chlorine gas (Cl2) is resting at 127 °C at a of pressure 152.4 kPa. If the gas weighs 191.4 g, what is the volume?
3. A 2.917 mole sample of an ideal gas at 285 K occupies a volume of 4.3 L. What is the pressure of the gas?
4. At what temperature would 2.10 moles of Kr gas have a pressure of 111.1 kPa and in a 25.0 L tank?
5. What is the volume of 146.2 grams of nitrogen gas (N2) molecules at STP?
6. What mass (NOT moles) of CO2 is needed to fill an 80.0 L tank to a pressure of 150.0 kPa at 27.0°C?
Answers
1. PV = nRT
2. PV = nRT and n = grams/molar mass
3. PV = nRT
4. {V = nRT
5. mols = grams/molar mass, then mols x 22.4L/mol at STP
6. PV = nRT, then n = grams/molar mass.
Remember in these problems that if you you atmospheres for pressure then R is 0.08206. If you use P in kPa, then R is 8.314.
2. PV = nRT and n = grams/molar mass
3. PV = nRT
4. {V = nRT
5. mols = grams/molar mass, then mols x 22.4L/mol at STP
6. PV = nRT, then n = grams/molar mass.
Remember in these problems that if you you atmospheres for pressure then R is 0.08206. If you use P in kPa, then R is 8.314.
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