A plane is heading on a bearing of 200° with an air speed of 400 km/h when it is blown off course by a wind of 100 km/h from the northeast. Determine the resultant ground velocity of the plane. How did you get your answer?

Answer 1

Vr = 400km/h[200o] + 100km/h[225o]

X = 400*Cos200 + 100*Cos225 = -447 km/h
Y = 400*sin200 + 100*sin225 = -208 km/h

Tan Ar = Y/X = -208/-447 = 0.46532
Ar = 25o = Reference angle.
A = 25 + 180 = 205o (Q3).

V = X/Cos A = -447/Cos205 = 493 km/h. =
Resultant velocity.