Asked by Amyy
A plane is heading on a bearing of 200° with an air speed of 400 km/h when it is blown off course by a wind of 100 km/h from the northeast. Determine the resultant ground velocity of the plane. How did you get your answer?
Answers
Answered by
Henry
Vr = 400km/h[200o] + 100km/h[225o]
X = 400*Cos200 + 100*Cos225 = -447 km/h
Y = 400*sin200 + 100*sin225 = -208 km/h
Tan Ar = Y/X = -208/-447 = 0.46532
Ar = 25o = Reference angle.
A = 25 + 180 = 205o (Q3).
V = X/Cos A = -447/Cos205 = 493 km/h. =
Resultant velocity.
X = 400*Cos200 + 100*Cos225 = -447 km/h
Y = 400*sin200 + 100*sin225 = -208 km/h
Tan Ar = Y/X = -208/-447 = 0.46532
Ar = 25o = Reference angle.
A = 25 + 180 = 205o (Q3).
V = X/Cos A = -447/Cos205 = 493 km/h. =
Resultant velocity.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.