mols C2H5OH = grams/molar mass = ?
mols CH3COOH = grams/molar mass = ?
..C2H5OH + CH3COOH ==> CH3COOC2H5 + H2O
I..0.18......1.0.........0...........0
C...-x.......-x..........x...........x
E.0.18-x....1.0-x........x...........x
49.74/60 = about 0.829
so 1-x = 0.829 which makes x = 0.171
Substitute the values into the Kc expression and solve for Kc.
when 8.28g of ethanol were heated with 60g of ethanioc acid 49.74 of acid remain at equilibrium calcuma the value of k
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