The magnetic field of the Earth is 0.50 x 10-4 T in a certain location.
a) What will be in Newtons the force on a completely ionized carbon atom (Z = 6, A = 12) traveling with the solar wind with a velocity of 18.00 x 103 m/s perpendicular to the magnetic field?
b) How fast must the ionized carbon atom be moving (m/s) so that its weight is exactly balanced by the magnetic force acting on it? Express your answer in m/s.
2 answers
force=qvXB, right?
Yes, I found the force to be 8.64x10^-19, but the speed I can not figure out.