A 25,000 kg rocket ship near the surface of the Earth accelerates upwards due to a constant 1.25 MN of thrust from its engine. A simple pendulum on the ship is observed to complete 100 full swings in 75.0 s. What is the length of the string?
1. For a simple pendulum: T = 2π√(L/g)
T = 75.0/100 = .75 seconds/swing
g = 9.8 m/s^2
Using this equation to solve for L, I got 0.1396 m as the length of the string.
2. For the rocket: F = ma
F = 1.25 * 10^6 N
m = 25,000 kg
Solving for the acceleration of the rocket, I got a = 50 m/s^2.
3. For the length of the string, is it just 0.1396 m, or do I have to take into account the rocket's acceleration?
0 answers