Asked by Anonymous
A wheel 32.6 cm in diameter accelerates uniformly from 247 rpm to 378 rpm in 6.54 s. How far will a point on the edge of the wheel have traveled in this time
Answers
Answered by
Henry
Circumference = pi*Dia = 3.14 * 32.6cm = 102.4 cm = 1.024 m.
Vo = 247rev/60s. * 1.024m/rev=4.22 m/s.
V = 378rev/60s * 1.024m/rev = 6.45 m/s.
V = Vo + a*t
V = 6.45 m/s
Vo = 4.22 m/s
t = 6.54 s.
Solve for a.
d = Vo*t + 0.5a*t^2
Vo = 247rev/60s. * 1.024m/rev=4.22 m/s.
V = 378rev/60s * 1.024m/rev = 6.45 m/s.
V = Vo + a*t
V = 6.45 m/s
Vo = 4.22 m/s
t = 6.54 s.
Solve for a.
d = Vo*t + 0.5a*t^2
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