Asked by Morgan
You want to determine the heat of reaction when a sodium chloride solution is formed using a 10.0 g sample of NaCl(s) and 50.0 mL of water in a coffee cup calorimeter. Which of the following equations would you use? Assume the specific heat of the solution is the same as the specific heat of water.
A. q = (50.0 g)(4.18 J/g K)(Ti - Tf)
B. q = [(10.0 g)(4.18 J/g K)(Tf - Ti)]/[10.0 g/(58.44 g/mol)]
C. q = (60.0 g)(4.18 J/g K)(Tf - Ti)
D. q = [(60.0 g)(4.18 J/g K)(Tf - Ti)]/[10.0 g/(58.44 g/mol)]
E. q = (60.0 g)(4.18 J/g K)(Ti - Tf)
I keep second guessing myself could you tell me the right answer and explain it to me
A. q = (50.0 g)(4.18 J/g K)(Ti - Tf)
B. q = [(10.0 g)(4.18 J/g K)(Tf - Ti)]/[10.0 g/(58.44 g/mol)]
C. q = (60.0 g)(4.18 J/g K)(Tf - Ti)
D. q = [(60.0 g)(4.18 J/g K)(Tf - Ti)]/[10.0 g/(58.44 g/mol)]
E. q = (60.0 g)(4.18 J/g K)(Ti - Tf)
I keep second guessing myself could you tell me the right answer and explain it to me
Answers
Answered by
DrBob222
Morgan, I've struggled with this question and looked in all of my references + web. Finally I've had to conclude that I simply don't have enough understanding about the answered listed to give an unequivocal response so the safe thing to do is to leave it alone. Sorry about that.
Answered by
Morgan
Should I go with c or d?
Answered by
DrBob222
If I knew the answer to your last response I could have answered it in the first place.
Answered by
Morgan
the answer is d I illuminated a and b because I knew that Tf has to be subtracted by ti. Next I illustrated b because I knew the mass had to be that of water or the total. FInally, I used the formal for c before and my number was to high so division made sense I hope you can use this to help other students as well. I have a question though, are you like a chemistry professor or a college student to just really good at chemistry?
Answered by
person
morgan how do you know its D?
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