Ft = Fc = (mv²)/r
59 = [m(20²)]/2.55
59(2.55) = 400m
150.45 = 400m
m = 0.376125 kg
Ft = Fc = (mv²)/r
Ft = [(0.376125)(52.5²)]/2.55
Ft = 406.546875 N
A string under a tension of 59.0 N is used to whirl a rock in a horizontal circle of radius 2.55 m at a speed of 20.0 m/s on a frictionless surface as shown in the figure below. As the string is pulled in, the speed of the rock increases. When the string on the table is 1.00 m long and the speed of the rock is 52.5 m/s, the string breaks. What is the breaking strength, in newtons, of the string?
1 answer
1 answer