Asked by Jake
If a quadratic has a vertex at (-2,2) and passes through (-1,0) what is its equation in standard form?
A. y = -2(x-2)^2 + 2
B. y = -2(x+2)^2 + 2
C. y = -(x+2)^2 - 2
D. y = (x+2)^2 + 2
Is the answer B?
A. y = -2(x-2)^2 + 2
B. y = -2(x+2)^2 + 2
C. y = -(x+2)^2 - 2
D. y = (x+2)^2 + 2
Is the answer B?
Answers
Answered by
bobpursley
of course, B
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