6log2^3 √64+ 10log3^5 √243
= 6log(8*8) + 10log(243√243)
= log 64^10 + log ( (243√243)^10)
= log ( (64^10)(243√243)^10 )
= log ( (64^10)(243^15) )
= log (7.0128 x 10^35)
= appr 53.85
I suspect a typo
Evaluate
6log2^3 √64+ 10log3^5 √243
2 answers
yes there is a typo
6 log2 ∛64 + 10log3 (243)^1/5
6 log2 ∛64 + 10log3 (243)^1/5
2 answers