If a reaction has a percentage yield of 83.0%, what mass of methane can be obtained from 1150 g of carbon?

Question

2 C(s) + 2 H2O(l) CH4(g) + CO2(g)

*Answer in grams*

Answer 1

mols C = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols C to mols CH4.
?C x (1 mol CH4/2 mols C) = ? mols CH4.

Convert mols CH4 to grams by g = mols CH4 x molar mass CH4 = ? g CH4. This is for 100% yield.
But you will get only 83.0% of that so
g for 100% yield x 0.830 = ? g for 83^ yield.