Question

1).Find the sum of the n terms of the series Sn=1^2 + 3^2 +5^2+...+(2n-1)^2

2).Find the sum to n terms of 1/(1.2.3) + 3/(2.3.4) + 5/(3.4.5) + 7/(4.5.6) +....

3) Sum to n terms,the series 1.3.5 + 2.4.6 + 3.5.7 +.

Answer 1

I answered the first part in your previous post

Answer 2

Still messing around with #2

#3,
∑ k(k+2)(k+4) , where k = 1 to n

if you expand this you will get a cubic , so you will have to have
∑ k^3 for k=1 to n equal to (1/4)n^2(n+1)^2
( I had to look that one up)

for the square and first degree terms use the ones I gave you in #1

good luck

Answer 3

n
∑ (2k-1)/[k(k+1)(k+2) =
k=1

n(3n+1)
--------------
4(n+1)(n+2)