Asked by Sara
what is the difference between the function 2^x and (1/2)^x?
Answers
Answered by
Steve
well, (1/2) = 2^-1
go to wolframalpha.com and enter
plot y=2^x, y=(1/2)^x
go to wolframalpha.com and enter
plot y=2^x, y=(1/2)^x
Answered by
Sara
Oh ok! so 2^x is the inverse of (1/2)^x
Answered by
Reiny
the difference between the function 2^x and (1/2)^x
= |2^x - (1/2)^x|
= | 2^x - 2^-x |
= |2^x - (1/2)^x|
= | 2^x - 2^-x |
Answered by
Sara
Oh I wrote the question incorrect. It's not to find the difference but to explain the difference between the two functions
Answered by
Reiny
then go with Steve's suggestion and plot the two curves
y = 2^x and y=(1/2)^x to see the result
http://www.wolframalpha.com/input/?i=plot+y+%3D+2%5Ex+%2C+y+%3D+%281%2F2%29%5Ex
y = 2^x and y=(1/2)^x to see the result
http://www.wolframalpha.com/input/?i=plot+y+%3D+2%5Ex+%2C+y+%3D+%281%2F2%29%5Ex
Answered by
Steve
2^x is not the inverse of (1/2)^x
log_2(x) is the inverse of 2^x
log_1/2(x) is the inverse of (1/2)^x
You can check this because if g(x) is the inverse of f(x), f(g(x)) = x and g(f(x)) = x
(1/2)^x = 1/2^x
they are reciprocals, not inverses.
log_2(x) is the inverse of 2^x
log_1/2(x) is the inverse of (1/2)^x
You can check this because if g(x) is the inverse of f(x), f(g(x)) = x and g(f(x)) = x
(1/2)^x = 1/2^x
they are reciprocals, not inverses.
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