Asked by qwerty
You roll two five-sided dice. The sides of each die are numbered from 1 to 5. The dice are “fair" (all sides are equally likely), and the two die rolls are independent.
Part (a): Event A is “the total is 10" (i.e., the sum of the results of the two die rolls is 10).
Is event A independent of the event “at least one of the dice resulted in a 5"?
- unanswered
Is event A independent of the event “at least one of the dice resulted in a 1"?
- unanswered
Part (b): Event B is “the total is 8."
Is event B independent of getting “doubles" (i.e., both dice resulting in the same number)?
- unanswered
Given that the total was 8, what is the probability that at least one of the dice resulted in a 3?
Part (a): Event A is “the total is 10" (i.e., the sum of the results of the two die rolls is 10).
Is event A independent of the event “at least one of the dice resulted in a 5"?
- unanswered
Is event A independent of the event “at least one of the dice resulted in a 1"?
- unanswered
Part (b): Event B is “the total is 8."
Is event B independent of getting “doubles" (i.e., both dice resulting in the same number)?
- unanswered
Given that the total was 8, what is the probability that at least one of the dice resulted in a 3?
Answers
Answered by
RVE
part (a)
1 and 2 No.
part (b)
1. No.
2. Looks like conditional probability (i failed this question. This answer was not used back in the day)
scenarios:
(the only possibility for an 8)
3,5 =0.2*0.2
4,4=0.2*0.2
5,3=0.2*0.2
at least one of the dices was a 3?
So thus = 0.08/0.12 =0.66666667
hope it helps!
1 and 2 No.
part (b)
1. No.
2. Looks like conditional probability (i failed this question. This answer was not used back in the day)
scenarios:
(the only possibility for an 8)
3,5 =0.2*0.2
4,4=0.2*0.2
5,3=0.2*0.2
at least one of the dices was a 3?
So thus = 0.08/0.12 =0.66666667
hope it helps!
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