Asked by Anonymous

A person stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.69 of the person's regular weight. Calculate the magnitude of the acceleration of the elevator.

Answers

Answered by Caleb
m= 0.69

a=mg-g

a=(0.69)(9.80)-9.80

a=-3.038 m/s^2

Acceleration is 3.038 m/s^2 downward
Answered by jame
cheese technique
Answered by flintesto
no
Answered by a
A person stand on bathroom scale in motionless elevator. When elevator begins to move the briefly reads

only 0.54 of the person's regular weight. Calculate acceleration of elevator.

Answered by Nav
Fnet = ma
ma = Fn-Fg
Fn = 0.69Fg = 0.69mg
Fg = mg
ma = 0.69mg - mg
cancel out all m in equation and left with:
a=0.69g-g
a=-.31g=-.31*9.8= -3.04 m/s^2
ANSWER: a = -3.04 m/s^2
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