Asked by Anonymous
A person stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.69 of the person's regular weight. Calculate the magnitude of the acceleration of the elevator.
Answers
Answered by
Caleb
m= 0.69
a=mg-g
a=(0.69)(9.80)-9.80
a=-3.038 m/s^2
Acceleration is 3.038 m/s^2 downward
a=mg-g
a=(0.69)(9.80)-9.80
a=-3.038 m/s^2
Acceleration is 3.038 m/s^2 downward
Answered by
jame
cheese technique
Answered by
flintesto
no
Answered by
a
A person stand on bathroom scale in motionless elevator. When elevator begins to move the briefly reads
only 0.54 of the person's regular weight. Calculate acceleration of elevator.
only 0.54 of the person's regular weight. Calculate acceleration of elevator.
Answered by
Nav
Fnet = ma
ma = Fn-Fg
Fn = 0.69Fg = 0.69mg
Fg = mg
ma = 0.69mg - mg
cancel out all m in equation and left with:
a=0.69g-g
a=-.31g=-.31*9.8= -3.04 m/s^2
ANSWER: a = -3.04 m/s^2
ma = Fn-Fg
Fn = 0.69Fg = 0.69mg
Fg = mg
ma = 0.69mg - mg
cancel out all m in equation and left with:
a=0.69g-g
a=-.31g=-.31*9.8= -3.04 m/s^2
ANSWER: a = -3.04 m/s^2
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