Asked by Christian
A skier moves 100.0 m horizontally, and then travels another 35.0 m uphill at an angle of 35.0º above the horizontal. What is the skier's displacement from his starting point?
Answers
Answered by
Damon
horizontal
x = 100 + 35 cos 35
vertical
y = 35 sin 35
or
sqrt(x^2+y^2) at tan^-1(y/x) above x axis
x = 100 + 35 cos 35
vertical
y = 35 sin 35
or
sqrt(x^2+y^2) at tan^-1(y/x) above x axis
Answered by
TINYA
A skier moves 100.0 m horizontally, and then travels another 35.0 m uphill at an angle of 35.0º above the horizontal. What is the skier's displacement from his starting point?
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