Question
Given that the initial rate constant is 0.0190s−1 at an initial temperature of 22 ∘C , what would the rate constant be at a temperature of 190 ∘C for the same reaction described in Part A?
Activation Energy 32.4kJ/mol
Activation Energy 32.4kJ/mol
Answers
Tia
Use the Arrhenius equation. It should be 1.2
DrBob222
Post your work if you get stuck.