Asked by Paul

the length of a rectangle is 7 meters more than twice the width. the perimeter is 68 meters. solve for length and width.

I need this step by step using the blueprint...please.
Answered by PsyDAG
No blueprint available.

L = 2W + 7

2W + 2L = 68

Substitute 2W+7 for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.
Answered by elvin
150
Answered by Nimo
he length of a rectangle is 7 meters more than twice the width. the perimeter is 68 meters. solve for length and width.
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