2(q^2-3q) = 2q^2-6q
So, you want to add up
2q^2-6q+q+10+q^2
Keep like powers together, and you end up with
(2+1)q^2 + (=6+1)q + 10
3q^2-5q+10
How do i find the perimeter of a triangle with variables?
one side is 2(q^2 - 3q), the second side is q + 10 and the third side is q^2.
how do i add all of these sides
1 answer