Asked by Steve

A carpenter is putting a skylight on a roof. If the roof measures 10x +89 by 7x+7 and the skylight measures x+5 by 3x+3, what is the area of the remaining roof after the skylight is built?
Answered by Reiny
outer area = (10x+89)(7x+7)= 70x^2 + 693x + 623
skylight area = (x+5)(3x+3)= 3x^2 + 18x + 15

remaining area = 70x^2+693x+623 - (3x^2+18x+15)
= 67x^2 + 675x + 608
Answered by Steve
thank you
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