Asked by Zach
                divide using long division.
(6x^2+4x-16)/(2x-2)
            
        (6x^2+4x-16)/(2x-2)
Answers
                    Answered by
            Reiny
            
    first of all notice that each term divides by 2, so
(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)
hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
    
(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)
hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
                    Answered by
            Steve
            
    a good long division site is
http://calc101.com/webMathematica/long-divide.jsp
    
http://calc101.com/webMathematica/long-divide.jsp
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.