Asked by Zach
divide using long division.
(6x^2+4x-16)/(2x-2)
(6x^2+4x-16)/(2x-2)
Answers
Answered by
Reiny
first of all notice that each term divides by 2, so
(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)
hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)
hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
Answered by
Steve
a good long division site is
http://calc101.com/webMathematica/long-divide.jsp
http://calc101.com/webMathematica/long-divide.jsp