Asked by Zach

divide using long division.
(6x^2+4x-16)/(2x-2)

Answers

Answered by Reiny
first of all notice that each term divides by 2, so

(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)

hard to show the actual long division on here but you should get 3x+5 with a remainder of -3
Answered by Steve
a good long division site is

http://calc101.com/webMathematica/long-divide.jsp
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