divide using long division.

Question

(6x^2+4x-16)/(2x-2)

Answer 1

first of all notice that each term divides by 2, so

(6x^2+4x-16)/(2x-2)
= (3x^2 + 2x-8)/(x-1)

hard to show the actual long division on here but you should get 3x+5 with a remainder of -3

Answer 2

a good long division site is

http://calc101.com/webMathematica/long-divide.jsp