Asked by Dave
Length of a side on a square is 5cm longer than the side of another square. the total area is 193cm. what is length of original?
Answers
Answered by
Reiny
area of first = x^2
area of 2nd = (x+5)^2
x^2 + x^2 + 10x + 25 = 193
2x^2 + 10x - 168 = 0
x^2 + 5x - 84 = 0
(x - 7)(x + 12) = 0
x = 7 or x = -12 , which would be a silly square
the first square is 7 by 7
the second is 12 by 12
check: 49 + 144 = 193 , yeahhh!
area of 2nd = (x+5)^2
x^2 + x^2 + 10x + 25 = 193
2x^2 + 10x - 168 = 0
x^2 + 5x - 84 = 0
(x - 7)(x + 12) = 0
x = 7 or x = -12 , which would be a silly square
the first square is 7 by 7
the second is 12 by 12
check: 49 + 144 = 193 , yeahhh!
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