Solve for x and y where needed

Question

A.4([1]/[2]x + 2)=2([2]/[3]x - 3)

B.[3x -6]/[2y]=4........equation one
[2y+3]/[4]=2x

Keys- [numerator]/[denominator]

Answer 1

Using somewhat more conventional notation, we have

4((1/2)x+2) = 2((2/3)x-3)
2x+8 = (4/3)x-6
(2/3)x = -14
x = -21

(3x-6)/(2y) = 4
3x-6 = 8y
3x-8y = 6

(2y+3)/4 = 2x
2y+3 = 8x
8x-2y = 3

Doing a little scaling, that's the same as

3x-8y = 6
32x-8y = 12
Now subtract and you have
29x = 6
x = 6/29
and now you can find y = -39/58