Asked by Anonymous
Use a(t)=-32 ft/second squared as the acceleration due to gravity. A ball is thrown vertically upward from the ground with an initial velocity of 96 feet per second. How high will it go?
Answers
Answered by
Reiny
height = -16t^2 + 96t
v = -32t + 96
= 0 at the top
32t=96
t = 3
it will take 3 seconds to reach the max, and that
max is
-16(9) + 96(3) = 144 ft
v = -32t + 96
= 0 at the top
32t=96
t = 3
it will take 3 seconds to reach the max, and that
max is
-16(9) + 96(3) = 144 ft
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