Asked by kobe
At the beginning of a titration to standardize the NaOH solution, Student A adjusted very carefully the initial burette volume to 0.00 mL, but he did not notice an important air bubble in the tip of the burette. At the end of the titration, the air bubble is gone. Explain the effect of that mistake on the calculated molarity MB. (Will the experimental MB calculated by Student A be higher or lower than the true MB value?)
Answers
Answered by
DrBob222
The bubble is gone which means the volume measured is the volume of the titration + the volume of bubble; i.e., it is too large.
If you are doing a titration with acid so that mL acid x M acid = ml base x M base, then
Mbase = mLacid x Macid/mL base
So mL base is too large how will that affect the answer?
If you are doing a titration with acid so that mL acid x M acid = ml base x M base, then
Mbase = mLacid x Macid/mL base
So mL base is too large how will that affect the answer?
Answered by
Giller
McGill chem lab report?
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