(SO2) = 4 mol/2L = 2M
(O2) = 5 mol/2L = 2.5M
.......2SO2 + O2 = 2SO3
I.......2M...2.5M....0
C......-2x...-x......2x
E......2-2x..2.5-x...2x
I presume you mean (O2) AT EQUILIBRIUM is 2M. That means 2.5-x = 2; therefore, x = 0.5. Evaluate SO2 and SO3 at 4equilibrium, substitute into Kc expression and solve for Kc.
2SO2 + O2 = 2SO3
4.00 mols of SO2 5.00 mol of O2 in 2L of a container at 200 degrees celcius. Concentration of O2 is 2M calculate the Kc
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