Question

A uniform rod of weight 5N and lenght 1m is pivoted at a point of 20 cm from one of its ends. A weight is hung from the other end so that te rod balances horizontally. What is the value of the weight?

How do I find it if I don't know the weight at the other end?
bobpursley
sum moments about any point.
Lets sum moments near where the weight is.

W*0 + 5*.5 - (W+5)*.2=0

2.5=(w+5).2
solve for w, in newtons.


Related Questions

A uniform bar length of 2.0m and weight 1000 N has its center of gravity at its center. The bar is p... A uniform rod 30cm long is pivoted at it's center. A 40N weight is hung 5cm from the left end. where... A uniform rod of weight 5N and length 1m is pivoted at the 20cm mark from one end. A weight is hung... A uniform meter rule which is pivoted at the 20cm mark and balanced horizontally by an object of wei...