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Assume diameter of a neutral helium atom is 1.40x10^2pm. Suppose that we could line up helium atoms side by side in contact with one another. How many atoms would it take to complete the distance of 6.70cm from end to end?
10 years ago

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DrBob222
140 pm/atom x #atoms = 6.70E10 pm
10 years ago
wank
6.70 X 10^8
8 years ago

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