Asked by Chessy
A 15 m flagpole stands on level ground. from point P, due west of the flagpole the angle of elevation of the top of the pole is 38 degrees. From point Q, due north of the flagpole, the flagpole has an angle of elevation of 25 degrees. Find the distance of PQ, correct to one decimal place.
Answers
Answered by
Reiny
Label the top of the pole as T and its base as O
in triangle OTP,
tan38 = 15/OP
OP = 15/tan 38
in triangle TOP,
cos 25 + 15/OQ
OQ = 15/tan25
in the right-angled triangle POQ
PQ^2 = OP^2 + OQ^2
I will let you finish it.
in triangle OTP,
tan38 = 15/OP
OP = 15/tan 38
in triangle TOP,
cos 25 + 15/OQ
OQ = 15/tan25
in the right-angled triangle POQ
PQ^2 = OP^2 + OQ^2
I will let you finish it.
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