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A fire hose ejects a stream of water at an angle of 29.0° above the horizontal. The water leaves the nozzle with a speed of 31....Asked by V
A fire hose ejects a stream of water at an angle of 33.4 ° above the horizontal. The water leaves the nozzle with a speed of 20.1 m/s. Assuming that the water behaves like a projectile, how far from a building should the fire hose be located to hit the highest possible fire?
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Answered by
Damon
v = Vi - 9.81 t
at top v = 0
t = Vi/9.81 at top
Vi = 20.1 sin 33.4 = 11.1
so t = 11.1/9.81 = 1.13 seconds at top
how far horizontal in 1.13 seconds?
u = 20.1 cos 33.4 = 16.8 m/s
16.8 m/s * 1.13 s = 19 meters
at top v = 0
t = Vi/9.81 at top
Vi = 20.1 sin 33.4 = 11.1
so t = 11.1/9.81 = 1.13 seconds at top
how far horizontal in 1.13 seconds?
u = 20.1 cos 33.4 = 16.8 m/s
16.8 m/s * 1.13 s = 19 meters
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