Question

A rectangular tank of base 2.4 m by 2.8 m and a height of 3 m contain 3,600 liters of water initially. Water flows into the tank at the rate of 0.5 liters per second
Calculate the time in hours and minutes, required to fill the tank

Answer 1

2.4 * 2.8 * 3 = 20.16 m^3

1 m^3 = 1000 liters

so V tank = 20,160 liters
we have 3,600 liters
so must deliver 16,560 liters

16,560 liters / .5 liters/s = 33,120 seconds
/3600 = 9.2 hours
9 hours and 12 minutes

Answer 2

Amount needed to fill the tank:2.4*2.8*3=20.16m³.since 1m³=1000litres therefore volume:20.16*1000=20160litres. Remaining:20160-3600=16560litres.
If 0.5litres=1sec what about 16560litres:16560/0.5=33120s. But 1min=60sec what about 33120sec:33120/60=552min therefore 552/60=?

9hrs 12min.