Asked by Harry
A company has four production sections viz., S1, S2, S3 and S4 which contribute 30%, 20%, 28% and 22% of the total output. It was observed that those sections respectively produced 1%, 2%, 3% and 4% defective units. If a unit is selected at random and found to be defective, what is the probability that the unit so selected has come from either S1 or S4.
Answers
Answered by
Teja
Answer pls
Answered by
tuttu
ariyilla
Answered by
Deep Akabari
Hint: We know
P(S1)=0.30, P(S2)=0.20, P(S3)=0.28, P(S4)=0.22. If D is the defect case than we know also P(D|S1)=0.01, P(D|S2)=0.02, P(D|S3)=0.03,and P(D|S4)=0.04.
Now, the question is asking you to determine P(S1|D)+P(S4|D). Can you determine these probabilities with the Bayes' theorem?
P(S1)=0.30, P(S2)=0.20, P(S3)=0.28, P(S4)=0.22. If D is the defect case than we know also P(D|S1)=0.01, P(D|S2)=0.02, P(D|S3)=0.03,and P(D|S4)=0.04.
Now, the question is asking you to determine P(S1|D)+P(S4|D). Can you determine these probabilities with the Bayes' theorem?
Answered by
Praveena
0.59
Answered by
Praveena
0.49
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