Asked by slomo
Multiply and simplify. Assume that no radicands were formed by raising negative numbers to even powers.
√6x3 √18x2
I have never been good at figuring this formula out with square roots and I am practicing for a test next week and I really want to graduate so if you can show me how to do the steps to this problem. Please and Thank you
√6x3 √18x2
I have never been good at figuring this formula out with square roots and I am practicing for a test next week and I really want to graduate so if you can show me how to do the steps to this problem. Please and Thank you
Answers
Answered by
Reiny
You must know the first few perfect squares, such as
4, 9, 16, 25,... perhaps up to 144
so for √(any number) , attempt to split the number into factors containing one or more of those perfect squares.
e.g. √18 = √9 √2 = 3√2
√35 = √5√7 , nothing gained because neither 5 nor 7 is a perfect square.
If you have large numbers under the square root, such as
√1344
factor 1344 and hope to find a perfect square
e.g.
1344 = 4x336
= 4x4x84
= 4x4x4x21
= 64x21
So √1344 = √64√21 = 8√21
if you have √'s of variable powers, break them up into even exponent roots
remember √x^ = x
√x^4 = x^2
√x^6 = x^3 etc
e.g. √x^13
= √x^12 √x
= x^6 √x
Your last problem:
√18x2
= √9√2√x^2
= (3)(√2)(x)
= 3x√2
4, 9, 16, 25,... perhaps up to 144
so for √(any number) , attempt to split the number into factors containing one or more of those perfect squares.
e.g. √18 = √9 √2 = 3√2
√35 = √5√7 , nothing gained because neither 5 nor 7 is a perfect square.
If you have large numbers under the square root, such as
√1344
factor 1344 and hope to find a perfect square
e.g.
1344 = 4x336
= 4x4x84
= 4x4x4x21
= 64x21
So √1344 = √64√21 = 8√21
if you have √'s of variable powers, break them up into even exponent roots
remember √x^ = x
√x^4 = x^2
√x^6 = x^3 etc
e.g. √x^13
= √x^12 √x
= x^6 √x
Your last problem:
√18x2
= √9√2√x^2
= (3)(√2)(x)
= 3x√2
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