Asked by kudu
The velocity V ms^-1, of a moving body at time t seconds is given V = 5t^2 – 12t + 7
Calculate the acceleration when t = 2 seconds
Calculate the acceleration when t = 2 seconds
Answers
Answered by
Henry
Vo = 5*0^2 - 12*0 + 7 = 7 m/s. t = 0.
V = 5*2^2 - 12*2 * 7 = 3 m/s. t = 2 s.
a = (V-Vo)/t = (3-7)/2 = -2 m/s^2.
V = 5*2^2 - 12*2 * 7 = 3 m/s. t = 2 s.
a = (V-Vo)/t = (3-7)/2 = -2 m/s^2.
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