Asked by Jessica
Benzene has a vapor pressure of 183 mm Hg at 40 degrees Celsius. Taking it's heat of vaporization to be 30.8 kJ/mol, calculate it's vapor pressure at 25 degrees Celsius. The answer is 101 mm Hg, but I keep getting 4.613, and I can't figure out where 101 mm Hg comes from.
ln 183-lnP1= 30.8 kJ/mol/8.31x10-3 ((1/298)-(1/313))
5.209-lnP1=0.596, therefore, ln P1 should equal 4.613.
ln 183-lnP1= 30.8 kJ/mol/8.31x10-3 ((1/298)-(1/313))
5.209-lnP1=0.596, therefore, ln P1 should equal 4.613.
Answers
Answered by
DrBob222
Thank you for showing your work.
You have done everything exactly right EXCEPT you have one more step to go through. Your answer is
ln p1 = 4.613.
Find the number for which ln p = 4.613 and it is about 100.7 which rounds to 101 mm. :-)
You have done everything exactly right EXCEPT you have one more step to go through. Your answer is
ln p1 = 4.613.
Find the number for which ln p = 4.613 and it is about 100.7 which rounds to 101 mm. :-)
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