......Ba3(PO4)2 ==> 3Ba^2+ + 2PO4^3-
I.....solid..........0..........0
C.....solid..........3x.........2x
E.....solid..........3x.........2x
Ksp = (Ba^2+)^3(PO4^3-)^2
Substitute the E line into Ksp expression and solvle for x. That gives you the solubility of the solid.
Can someone please help me solve this problem?
Calculate the solubility of Ba3(PO4)2 in water. For Ba3(PO4)2, Ksp = 1.3 x 10- 29
Thank you!
1 answer