Asked by Anonymous
Can someone please help me solve this problem?
Calculate the solubility of Ba3(PO4)2 in water. For Ba3(PO4)2, Ksp = 1.3 x 10- 29
Thank you!
Calculate the solubility of Ba3(PO4)2 in water. For Ba3(PO4)2, Ksp = 1.3 x 10- 29
Thank you!
Answers
Answered by
DrBob222
......Ba3(PO4)2 ==> 3Ba^2+ + 2PO4^3-
I.....solid..........0..........0
C.....solid..........3x.........2x
E.....solid..........3x.........2x
Ksp = (Ba^2+)^3(PO4^3-)^2
Substitute the E line into Ksp expression and solvle for x. That gives you the solubility of the solid.
I.....solid..........0..........0
C.....solid..........3x.........2x
E.....solid..........3x.........2x
Ksp = (Ba^2+)^3(PO4^3-)^2
Substitute the E line into Ksp expression and solvle for x. That gives you the solubility of the solid.
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