Asked by LAIALI
Vector A with arrow is directed along the positive y-axis and has magnitude 9.0 units. Vector B with arrow is directed along the negative x-axis and has magnitude 4.0 unit.
(a) What are the magnitude and direction of A with arrow + B with arrow?
magnitude
Incorrect: Your answer is incorrect.
unit(s)
direction ° counterclockwise from the +x-axis
(b) What are the magnitude and direction of A with arrow − B with arrow?
magnitude unit(s)
direction ° counterclockwise from the +x-axis
(c) What are the x- and y-components of B with arrow − A with arrow?
x =
y =
(a) What are the magnitude and direction of A with arrow + B with arrow?
magnitude
Incorrect: Your answer is incorrect.
unit(s)
direction ° counterclockwise from the +x-axis
(b) What are the magnitude and direction of A with arrow − B with arrow?
magnitude unit(s)
direction ° counterclockwise from the +x-axis
(c) What are the x- and y-components of B with arrow − A with arrow?
x =
y =
Answers
Answered by
Henry
With Arrow
A = 9i
B = -4
a. A+B = 9i + (-4) Q2.
A+B = sqrt(9^2+(-4^2) = 9.85 Units.
Tan Theta = 9/-4 = -2.25
Theta = -66.0 + 180 = 114o, CCW(Q2).
b. A-B = 9i - (-4) = 9i + 4
A-B = sqrt(9^2+4^2) = 9.85 Units.
Tan Theta = 9/4 = 2.25
Theta = 66o
c. B-A = -4 - 9i
X = -4
Y = -9
A = 9i
B = -4
a. A+B = 9i + (-4) Q2.
A+B = sqrt(9^2+(-4^2) = 9.85 Units.
Tan Theta = 9/-4 = -2.25
Theta = -66.0 + 180 = 114o, CCW(Q2).
b. A-B = 9i - (-4) = 9i + 4
A-B = sqrt(9^2+4^2) = 9.85 Units.
Tan Theta = 9/4 = 2.25
Theta = 66o
c. B-A = -4 - 9i
X = -4
Y = -9
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